6 eggs were bought at a supermarket

The zoo needed to raise 25000.zoo officials planned a dinner/dance event and charged $300 per couple. What is the fewest number

garri49 [273]

83.3333333 is the answer rounded to 83

6 0

3 years ago

Read 2 more answers

The number of peanuts in bags is normally distributed with a mean of 184.7 peanuts

ioda

Standard deviation = 3.3

The data point = 178

The mean = 184.7

<h2>Further Explanation</h2>

To calculate the Z-score of a bag containing 178 peanuts, we should use the formula to calculating a z-score.

The formula for calculating a Z-score is as follows

$z = \frac{data Point - Mean}{Standard Deviation}$

This also implies

$z = \frac{178 - 184.7}{3.3}$

$Z= -2.03$

therefore, the correct answer is -2.03

A z-score determine the number of standard deviation from the mean a data point is.

some important factors about z-score include:

if it is a positive z-score, it indicates the data point is above average
if it is a negative Z-score, it indicates the data point is below average
if the z-score is close to 0, it then means the data point is close to average
if the z-score is above 3 or below -3, it is considered to be unusual

Learn More about Z-score at:

brainly.com/question/12876715

#learnwithbrainly

8 0

2 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers

Please help me !! im stuck with this !

postnew [5]

There are 4 As and 3 Bs, so the ratio of Bs to the total number of As and Bs is ...

... (count of Bs) : (count of As + count of Bs)

... = 3 : (4 + 3)

... = 3 : 7

Expressed as a fraction, this is

... 3/7

6 0

3 years ago

) You are finally well!  But now your child is sick!  You know there have been mistakes in orders so you are on the internet t

rjkz [21]

Answer:

The doctor's dosage was not appropriate.

The right dosage is from 56.625 mg to 113.25 mg of Antibiotic to be given every 6 hour for the child with weight 25 lbs.

Step-by-step explanation:

It is given that 20 to 40 mg/kg/day is the recommended dosage.

Now, the doctor's order is 150 mg of antibiotic to be given every 6 hours. And my child weighs 25 lbs.

Now, 1 lb is equivalent to 0.453 kg.

So, my child's weight is (25 × 0.453) = 11.325 kg.

So, the doctor's order is 150 mg of antibiotic to be given every 6 hours for a child of weight 11.325 kg.

Hence, the dosage is [(150 × 4) ÷ 11.325] = 52.98 mg/kg/day.

So, this is not within the limit of 20 to 40 mg/kg/day.

Therefore, the doctor's dosage was not appropriate.

Now, let the appropriate dosage is x mg per every 6 hours for a child with weight 25 lbs i.e. 11.325 kg.

So, $20 \leq \frac{4x}{11.325} \leq 40$

⇒ $20\leq 0.3532x \leq 40$

⇒ $56.625 \leq x \leq 113.25$

So, the right dosage is from 56.625 mg to 113.25 mg of antibiotic to be given every 6 hours for the child with weight 25 lbs. (Answer)

5 0

3 years ago