3 years ago

Solve for B. R = x(A + B)

Mathematics

1 answer:

atroni [7]3 years ago

4 0

A= -bx+r/x Hope this helps :P

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Are there repeating Xs in the second map?

monitta

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3 years ago

Calculate the value of P and of Q that satisfy the following simultaneous linear equations.

luda_lava [24]

0.5p -3q =11
5p +6q =2

1) ×-2

--> 3. -p +6q =-22

2) - 3)

6p =24

p =4

sub into 2)

5(4) +6q =2

20 +6q =2

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3 years ago

Did I get it correct?

VikaD [51]

Answer:

No they are proprotional.

Step-by-step explanation:

the tables eqaution is

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7 0

2 years ago

Read 2 more answers

Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartF

Ghella [55]

Rahul use addition property of equality in step 2.

Solution:

The image of the question is attached below.

Step 1:

$$2 x-\frac{1}{4}-\frac{3}{5} x=\frac{55}{4}$

combine like terms together.

$$2 x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}$

To make the denominator same multiply and divide 2x by 5.

$$\frac{10}{5} x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}$

Step 2:

$$\frac{7}{5} x-\frac{1}{4}=\frac{55}{4}$

By addition property of equality, add $\frac{1}{4}$ on both side of the equation.

$$\frac{7}{5} x-\frac{1}{4}+\frac{1}{4}=\frac{55}{4}+\frac{1}{4}$

Step 3:

$$ \frac{7}{5} x=\frac{56}{4}$

Step 4:

Multiply by $\frac{5}{7}$ on both side of the equation.

$x=10$

Hence Rahul use addition property of equality in step 2.

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3 years ago

Read 2 more answers

In the triangle below, with right angle , suppose that and .

bazaltina [42]

Answer:

G= 60.5

E= 70.9

F= 90

........

.......

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2 years ago