Answer:
The probability of rolling a number less than or equal to 2, then rolling a prime number is .
Step-by-step explanation:
The sample space of rolling a number cube, numbered 1 - 6 is:
S = {1, 2, 3, 4, 5, 6}
The cube is rolled twice.
Denote the events as follows:
<em>A</em> = rolling a number less than or equal to 2 in the first roll
<em>B</em> = rolling a prime number in the second roll
The two events <em>A</em> and <em>B</em> are independent.
This is because the result of rolling the cube the second time will not be dependent on the result of the first roll.
Compute the value of P (A) as follows:
Favorable outcomes = {1, 2} = 2
P (A) = Favorable outcomes of <em>A</em> ÷ Total number of outcomes
Compute the value of P (B) as follows:
Favorable outcomes = {2, 3, 5} = 3
P (B) = Favorable outcomes of <em>B</em> ÷ Total number of outcomes
Compute the probability of rolling a number less than or equal to 2, then rolling a prime number as follows:
Thus, the probability of rolling a number less than or equal to 2, then rolling a prime number is .
