Work backwards with pythagoras' theorem:
c^2=a^2+b^2
Here, a and b both equal to x. Therefore, you can write this as 8^2=2x^2. So 64=2x^2. Sqrt on both sides to give you 8=2x, hence x=4. However I must warn you that this working out may have a flaw, as I found that x actually equals to 5.66

7 0

3 years ago

F(x)=4x+5whsts the value of. F(-3). Is

MArishka [77]

Figure out the value

8 0

3 years ago

Read 2 more answers

What is the value of -4 x ( 4 - 6 ) ?

Delicious77 [7]

Answer: 8

Step-by-step explanation:

4 0

3 years ago

Find the x-coordinate of the point on the graph of y=x^2 where the tangent line is parallel to the secant line that cuts the cur

jek_recluse [69]

First find the secant line. The slope of the secant line through $(-1,1)$ (when $x=-1$ ) and $(2,4)$ (when $x=2$ ) is the average rate of change of $y=x^2$ over the interval $[-1,2]$ :

$\text{slope}_{\text{secant}}=\dfrac{2^2-(-1)^2}{2-(-1)}=\dfrac33=1$

The tangent line to $y=x^2$ will have a slope determined by the derivative:

$y=x^2\implies y'=2x$

Both the secant and tangent will have the same slope when $2x=1$ , or when $x=\dfrac12$ .

4 0

3 years ago