So here are the rules of horizontal asymptotes:
- Degree of Numerator > Degree of Denominator: No horizontal asymptote
- Degree of Numerator = Degree of Denominator:

- Degree of Numerator < Degree of Denominator: y = 0
Looking at the rational function, since the degree of the numerator is 2 and the degree of the denominator is 1 (and 2 > 1), this means that <u>this function has no horizontal asymptote.</u>
We'll use the Law of Cosines
We'll call
side a = length 5
side b = length 8
side c = length 10
and their corresponding angles as A, B and C
"C" would be the largest angle
cos (C) = (a^2 + b^2 - c^2) / 2 * a * b
cos (C) = (5^2 + 8^2 - 10^2) / 2 * 5 * 8
cos (C) = 25 + 64 -100 / 80
cos (C) = -11 / 80
cos (C) =
<span>
<span>
<span>
-0.1375
</span>
</span>
</span>
arc cosine (
<span>
<span>
<span>
-0.1375
</span>
</span>
</span>
) = 97.903 Degrees
The largest angle is 97.903 Degrees
Answer:
=2mπ + π/3 for m ∈ Z.
Step-by-step explanation:
Given the equation
, we are to find all the values of
that satisfies the equation.

General solution for sin
is
= nπ + (-1)ⁿ ∝, where n ∈ Z.
If n is an even number say 2m, then
= (2m)π + ∝ where ∝ = 60° = π/3
Hence, the general solution to the equation will be
= 2mπ + π/3 for m ∈ Z.
Answer:43
Step-by-step explanation:
-6+12 equals 6 and 40-3 equals 37
37 plus 6 equals 43