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3 years ago

PLS PLS PlS PLS PLS HELP

Mathematics

2 answers:

Vadim26 [7]3 years ago

7 0

Answer:

use common sense!!!!!!!!!!!!!!!!!!!!!

lara31 [8.8K]3 years ago

5 0

Answer:

45 cm

Step-by-step explanation:

since perimeter of ABC is 42, you subtract 12 from 42 to give you 30, and since ABC is isosceles you divide 30 by 2 to give you 15 for AB and BC and because BDC is equilateral, 15, 15, 15 each side gives you 45 cm

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3.8+(−2.9) I just need the sum please!

Lapatulllka [165]

Answer:

3.8 + (-2.9) is the same as 3.8 - 2.9. That equals .9 or 0.9

Step-by-step explanation:

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3 years ago

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Find the value of k when 5^-3 + 5^-4 = 5^k x 5^-4

GalinKa [24]

Answer:

k= 6/5 or 1.12

Step-by-step explanation:

You isolate the variable by dividing each side by factors that don't contain the variable. This variable (K) is not a whole number so I gave you the fraction and rounded decimal form. Hope this helps :)

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3 years ago

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The "mammals" data set in the "MASS" library contains the result of a study of sleep in mammal species. 1 2 Load the "mammals" d

dusya [7]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

The probability that the random you randomly select species that are greater than 200 kg is = 7/62

Step-by-step explanation:

Step One: Load the data set in to the R work space

data(mammals,package="MASS")

attach(mammals)

Step 2 : Obtain the list of the species that are greater than 200 and store it on y variable.

y <- subset(mammals,body>200)

Step Three : Obtain the total size

nrow(mammals)

Step Four : Obtain the sum of species greater than 200

sum(body > 200)

total size = 62

size with body > 200 = 7

hence

required probability = 7/62

7 0

3 years ago

Find the appropriate function

Sati [7]

Answer:

y = 0.5sin(4x)

Step-by-step explanation:

y = A sin(B(x + C)) + D

amplitude is A = 0.5

B = 2π/period = 2π / (1/2 π) = 4

phase shift is C (positive is to the left) = 0

vertical shift is D = 0

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3 years ago

A bridge underpass in the shape of an elliptical arch, that is, half of an ellipse, is 40 feet wide and 13 feet high. An eight f

Liula [17]

Answer:

the truck should not be higher than 12.934 ft

Step-by-step explanation:

if the bridge underpass is half of an ellipse , then the arch function will be B(x,y) such that

x²/a² + y²/b² = 1 , for x≥0 and y≥0 and y=0 for x≤0

where x= width , y= height

for

a= length of the bridge underpass = 40 ft

b= height of the bridge underpass = 13 ft

x²/(40 ft)² + y²/(13 ft)² = 1

that represents all the points of the arch

the maximum height is reached when the truck touches the arch, then

for a point x= 4 ft wide , since 8 foot wide represents 4 foot to the left (x=-4) and 4 foot to the right (x=4)

then

(4 ft)²/(40 ft)² + y²/(13 ft)² = 1

1/100 - y²/(13 ft)² = 1

y/13 ft = √(1-1/100) = 3/10*√11

y= 3/10*√11 * 13 ft = 12.934 ft

y= 12.934 ft

then the truck should not be higher than 12.934 ft

7 0

3 years ago