Answer is A and B. Solutions are where the two graphs cross, so you just need to find those coordinates, which are (-5,-13) and (2,-6).
Observe the sequences below. I. 3, 6, 9, 12, ... II. 3, 9, 27, 81, III. 2, 4, 8, 16, ... IV. 3, 5, 7, 9, Which of these are geom
Sholpan [36]
Observe the sequences below. I. 3, 6, 9, 12, ... II. 3, 9, 27, 81, III. 2, 4, 8, 16, ... IV. 3, 5, 7, 9, Which of these are geometric sequences? III only O Il and me II and IV O I and
Step-by-step explanation:
1) x/20 = -9
By cross multiplication,
x = -180
2) -168 = -14k
k = -168/-14
k = 12
3) -5m = -50
m = 10
4) -320 = -20n
n = 16
5) -4 = x - 5
x = 1
6) -6(-8 + n) = -54
42 - 6n = -54
-6n = -54 -52
6n = 106
n = 17.6
7) 3(x - 9) = -3
3x - 27 = -3
3x = 24
x = 8
8) 9k + 3 = -78
9k = -81
k = -9
9)4 + (n/4) = 8
By taking LCM,
16 + n/4 = 8
16 + n = 32
n = 16
10) -5r + 7 = -73
-5r = -80
r = 16
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>
The answer is 28 sq. Units