this is gp because
because ratio of next term to previous term is always same.
8/16= 4/8 = 1/2
so common ratio is 1/2
first term is a = 16
so nth term of a gp is given as
Tn = ar^(n-1)
T10 = 16 × (1/2)^(10-1)
= 16 × (1/2)^9 = 1/32
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 
is 
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given
Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.
Substituting m1 we get m2 as
Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line is
The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
Learn more about Quadratic Equation from:
brainly.com/question/17177510
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Nick is incorrect because he subtracted 3-1 and 3-2. The answer is 1 3/4 It is that distance because 3 2/4-1 3/4=1 3/4.
