Boron trifluoride/Molar mass
67.81 g/mol
It seems like I begin to forget whole organic Chemistry. Anyway, the answer is 2-methylheptane-3-yne.
To build a name for this molecule, you need to:
1. Determine where there is the lowest chain beginning with the double, triple bond, or there is other thing for other types of organic molecules.. In this case you have one triplet bond, and the lowest chain there is the one that is below the bond.
2. In this small chain you see one "forks": CH3 and another CH3 go from the one CH. Put number 1 where there are the most number of such compounds, in this case it doesn't matter because we have one CH3 in one way and one CH3 in the another.
3. Determine the largest chain which surely has the triple bond. Put the numbers from 2 to the final beginning with CH3 where you put number 1. Your largest chain consists of 7 particles CH3, CH2, and CH.
4. You see that you also have one unnamed particle, the one which is "the other way" when you are in the CH which is below the triple bond on the picture. Its name will be 2-methyl because it is connected with particle #2 and it consists only of one carbon. If there were 2, it would be ethyl, and so on.
5. Finally, let's write a full name: put 2-methyl first, "2-methyl." Then, write a full name for the chain of 7 carbons, which has to be heptane, if it had 5, you would name it pentane, ethane, and so on. So, we have "2-methylheptane." Finally, you see that you have a triple bond after the carbon #3. Put a dash and the number of this carbon. "2-methylheptane-3" you should have. Since it is alkyne (organic molecule with one triple bond), you have to write "yne" at the end.
the final name is "2-methylheptane-3-yne." You can answer the question "explain your naming process" by using the answer I provided. Hope it helps. Good luck!
These are two questions and two answers.
Answers:
Explanation:
<u>1) Balanced chemical equation (given):</u>
- CO₂(g) + 4H₂(g) → CH₄(g) + 2H₂O(g)
<u>2) Part A: How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? </u>
a)<u> Mole ratios:</u>
- 1 moles CO₂(g) : 1 mole CH₄(g)
b) <u>Proportion:</u>
- 1 moles CO₂ / 1 mol CH₄ = 59.6 moles CO₂ / x
⇒ x = 59.6 mol CH₄ ← answer
<u>3) Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor? </u>
a) <u>Mole ratios:</u>
- 4 mol H₂(g) : 2 mol H₂O(g)
b) <u>Proportion:</u>
- 4 mol H₂ / 2 mol H₂O = x / 42.1 mol H₂O
⇒ x = 42.1 × 4 / 2 moles CH₄ = 84.2 mol H₂ (g) ← answer
Answer:
<h3>Answer is </h3>
A higher taxes on corporations
<h2 /><h2 /><h2>I hope you like it </h2>
Answer:
Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work. ... You have to exert a force AND move something to qualify as doing work.
Explanation: