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alexandr402 [8]
1 year ago
5

Malonate is a competitive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial preparation that is oxid

izing pyruvate as a substrate, which compound would you expect to decrease in concentration?.
Chemistry
2 answers:
fiasKO [112]1 year ago
5 0

In competitive inhibitor <u>fumarate </u>decrease in concentration.

A competitive inhibitor is any molecule that can bind to the energetic site of an enzyme with enough affinity such that it could compete with the enzyme's natural substrate and decrease enzyme hobby as a end result.

An instance of a competitive inhibitor is the antineoplastic drug methotrexate. Methotrexate has a structure similar to that of the vitamin folic acid. It acts through inhibiting the enzyme dihydrofolate reductase, stopping the regeneration of dihydrofolate from tetrahydrofolate.

In competitive inhibition, an inhibitor that resembles the ordinary substrate binds to the enzyme, typically at the active web site, and prevents the substrate from binding. At any given second, the enzyme may be sure to the inhibitor, the substrate, or neither, but it can not bind each on the equal time.

Learn more about competitive inhibitor here:- brainly.com/question/14944549

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NARA [144]1 year ago
3 0

Malonate is an aggressive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial education this is oxidizing pyruvate as a substrate, it is lower in attention<u> </u><u>Fumarate</u><u>.</u>

<u />

Succinate dehydrogenase is also known as mitochondrial complicated II, and inhibition of succinate dehydrogenase by means of dimethyl malonate has been said to suppress the production of pro-inflammatory cytokines.

Fumaric acid is an organic compound with the system HO₂CCH=CHCO₂H.  It has a fruit-like taste and has been used as a meal additive. . The salts and esters are referred to as fumarates. Fumarate also can consult with the C ₄H ₂O²⁻ ₄ ion.

Learn more about Fumarate here

brainly.com/question/17098570

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72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

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