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alexandr402 [8]
1 year ago
5

Malonate is a competitive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial preparation that is oxid

izing pyruvate as a substrate, which compound would you expect to decrease in concentration?.
Chemistry
2 answers:
fiasKO [112]1 year ago
5 0

In competitive inhibitor <u>fumarate </u>decrease in concentration.

A competitive inhibitor is any molecule that can bind to the energetic site of an enzyme with enough affinity such that it could compete with the enzyme's natural substrate and decrease enzyme hobby as a end result.

An instance of a competitive inhibitor is the antineoplastic drug methotrexate. Methotrexate has a structure similar to that of the vitamin folic acid. It acts through inhibiting the enzyme dihydrofolate reductase, stopping the regeneration of dihydrofolate from tetrahydrofolate.

In competitive inhibition, an inhibitor that resembles the ordinary substrate binds to the enzyme, typically at the active web site, and prevents the substrate from binding. At any given second, the enzyme may be sure to the inhibitor, the substrate, or neither, but it can not bind each on the equal time.

Learn more about competitive inhibitor here:- brainly.com/question/14944549

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NARA [144]1 year ago
3 0

Malonate is an aggressive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial education this is oxidizing pyruvate as a substrate, it is lower in attention<u> </u><u>Fumarate</u><u>.</u>

<u />

Succinate dehydrogenase is also known as mitochondrial complicated II, and inhibition of succinate dehydrogenase by means of dimethyl malonate has been said to suppress the production of pro-inflammatory cytokines.

Fumaric acid is an organic compound with the system HO₂CCH=CHCO₂H.  It has a fruit-like taste and has been used as a meal additive. . The salts and esters are referred to as fumarates. Fumarate also can consult with the C ₄H ₂O²⁻ ₄ ion.

Learn more about Fumarate here

brainly.com/question/17098570

#SPJ4

<u />

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7. A 2.0 L container had 0.40 mol of He(g) and 0.60 mol of Ar(g) at 25°C.
Finger [1]

Answer:

a) Ek Ar > Ek He

b) v Ar < v He

c) If v Ar = 431 m/s ⇒ v He = 1710.44 m/s

d) Pt = 12.218 atm

e) P He = 4.887 atm and P Ar = 7.33 atm

Explanation:

container:

∴ V = 2.0 L

∴ n He = 0.4 mol

∴ n Ar = 0.6 mol

∴ T = 25°C ≅ 298 K

a) Internal energy (U) :

∴ U = Ek + Ep = kinetic energy + potential energy

∴ Ep: the potential interaction energy is neglected, assuming ideal gas mixture

⇒ U = Ek = N(1/2mv²)= 3/2 NKT

∴ N = nNo ....number of moleculas

∴ K = 1.380 E-23 J/K....Boltzmann's constant

∴ No = 6.022 E23 molec/mol....Avogadro's number

for He:

⇒ N = (0.4)(6.022 E23) = 2.4088 E23 molec

⇒ Ek = (3/2)(2.4088 E23)(1.380 E-23 J/K)(298) = 1485.892 J

for Ar:

⇒ N = (0.6)(6.022 E23) = 3.6132 E 23 molec

⇒ Ek = (3/2)(3.6132 E23)(1.380 E-23 J/K)(298) = 2228.838 J

** Ar gas has a greater average kinetic energy

b) He:

∴ N(1/2)mv² = (3/2)NKT

⇒ mv² = 3KT

⇒ v² = 3KT/m

⇒ v = √3KT/m

∴ m He = (0.4 mol)(4.0026 g/mol) = 1.601 g He = 1.601 E-3 Kg He

⇒ v = √(3(1.380 E-23)(298)/(1.601 E-3)) = 2.776 E-9 m/s He

Ar:

∴ m Ar = (0.6)(39.948 g/mol) = 23.969 g = 0.0239 Kg Ar

⇒ v = 6.99 E-10 m/s

** v Ar < v He

c) r = V Ar / v He = (6.99 E-10 m/s)/(2.776 E-9 m/s) = 0.252

∴ If v Ar = 431 m/s

⇒ v He = v Ar/0.252 = 431 m/s / 0.252 = 1710.44 m/s

d) Pt = ntRT / V

∴ nt = 0.4 + 0.6 = 1 mol

⇒ Pt = (1mol)(0.082 atm.L/K.mol)(298 K)/(2.00 L) = 12.218 atm

e) P He = nRT/V = (0.4)(0.082)(298)/2 = 4.8872 atm

⇒ P Ar = Pt - PHe = 12.218 - 4.8872 = 7.33 atm

3 0
3 years ago
Balance the chemical equations.<br> 1FeCl3 + KOH → Fe(OH)3 + KC1
wariber [46]

Answer:

FeCl3 + 3KOH → Fe(OH)3 + 3KCl

Explanation:

3 0
3 years ago
The amount of energy required to heat water for a 10-minute shower (50 gallons) is 2.2125 kJ. How many calories is this
Alenkinab [10]
First, we convert the given amount of energy into joules.
1 kJ = 1000 joules
2.2125 kJ = 2,212.5 Joules

Each kilocalorie contains 4,184 Joules
Kilocalories = 2,212.5 / 4,182
Kilocalories = 0.529
1 kilocalorie = 1000 calories

0.529 kilocalories = 529 calories
6 0
3 years ago
What is another name for a beta minus (B-) particle?
pentagon [3]
<span>electron, I believe.
</span>
6 0
3 years ago
How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
3 years ago
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