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alexandr402 [8]
1 year ago
5

Malonate is a competitive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial preparation that is oxid

izing pyruvate as a substrate, which compound would you expect to decrease in concentration?.
Chemistry
2 answers:
fiasKO [112]1 year ago
5 0

In competitive inhibitor <u>fumarate </u>decrease in concentration.

A competitive inhibitor is any molecule that can bind to the energetic site of an enzyme with enough affinity such that it could compete with the enzyme's natural substrate and decrease enzyme hobby as a end result.

An instance of a competitive inhibitor is the antineoplastic drug methotrexate. Methotrexate has a structure similar to that of the vitamin folic acid. It acts through inhibiting the enzyme dihydrofolate reductase, stopping the regeneration of dihydrofolate from tetrahydrofolate.

In competitive inhibition, an inhibitor that resembles the ordinary substrate binds to the enzyme, typically at the active web site, and prevents the substrate from binding. At any given second, the enzyme may be sure to the inhibitor, the substrate, or neither, but it can not bind each on the equal time.

Learn more about competitive inhibitor here:- brainly.com/question/14944549

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NARA [144]1 year ago
3 0

Malonate is an aggressive inhibitor of succinate dehydrogenase. If malonate is added to a mitochondrial education this is oxidizing pyruvate as a substrate, it is lower in attention<u> </u><u>Fumarate</u><u>.</u>

<u />

Succinate dehydrogenase is also known as mitochondrial complicated II, and inhibition of succinate dehydrogenase by means of dimethyl malonate has been said to suppress the production of pro-inflammatory cytokines.

Fumaric acid is an organic compound with the system HO₂CCH=CHCO₂H.  It has a fruit-like taste and has been used as a meal additive. . The salts and esters are referred to as fumarates. Fumarate also can consult with the C ₄H ₂O²⁻ ₄ ion.

Learn more about Fumarate here

brainly.com/question/17098570

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Answer:

inversely proportional

Explanation:

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Suppose that NaCl is added to hexane (C6H14) instead of water. Which of the following intermolecular forces will exist in the sy
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Answer:

Ion-ion force between Na+ and Cl− ions

London dispersion force between two hexane molecules

Explanation:

"Ion-dipole force between Na+ ions and a hexane molecule " does not exist since hexane has only non-polar bonds and therefore no dipole.

"Ion-ion force between Na+ and Cl− ions " exists since both are ions.

"Dipole-dipole force between two hexane molecules " does not exist since hexane molecules do not have a dipole.

"Hydrogen bonding between Na+ ions and a hexane molecule " does not exist since the hydrogen in the hydrogen bond must be bonded directly to an electronegative atom, which hexane does not have since it is a hydrocarbon.

"London dispersion force between two hexane molecules" exist since hexane is a molecular compound.

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Rusting Out. How Acids Affect the Rate of corrosion
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Create a chemical equation for "Bubbling chlorine gas through a solution of sodium bromide gives elemental bromine and a solutio
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Answer:

Cl_{2} +2NaBr ---> 2NaCl + Br_{2}

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5 0
3 years ago
2. In Experiment SOL, you investigated the solubility of oxalic acid. Sodium oxalate, Na2C2O¬4, is the sodium salt of this acid.
AnnZ [28]

Answer:

Sodium oxalate is a basic salt. In water it can be dissolved and dissociated.

The oxalic acid in water has two dissociations.

Explanation:

Na2C2O4 ---> 2Na+   +  C2O4-2

Sodium oxalate is the conjugate base of a weak acid. In water this salt, dissociates completely giving rise to the sodium and oxalate ions. As Na+ comes from a strong base, in water it does not produce hydrolysis while oxalate does react in water, because it takes a proton from it and it generates a basic hydrolysis releasing OH-.

C2O4-2  + H2O ⇄  HC2O4-  +  OH-

In water the salt is basic.  The pH of an aqueous solution of this salt is basic, since OH- is generated.

The HC2O4- has a second hydrolisis, it takes another proton from water to form oxalic acid.

HC2O4-  +  H2O ⇄  H2C2O4  +  OH-

The oxalic acid acts as a weak acid, it can release 2 protons to water, to make oxalate (its conjugate base).

H2C2O4  + H2O ⇄ H3O+  + HC2O4-

HC2O4-  +  H2O ⇄  H3O+  C2O4-2

The  HC2O4-  acts as an ampholyte since it accepts and delivers protons simultaneously.

6 0
3 years ago
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