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3 years ago

Can one of y’all help me with this pls

Mathematics

2 answers:

Vladimir79 [104]3 years ago

8 0

So the answer is b because they’re asking you to find the number of boys in the classroom, so you need to add the number of girls and boys to figure out how many kids are in the classroom together.

Answer: B

Goshia [24]3 years ago

7 0

Answer:

B. 12/25

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PLEASE HELP 100 POINTS

Olin [163]

Answer:

see below

Step-by-step explanation:

$f(x)=2/x\\\\g(x)=2/x\\\\f(g(x))=f(2/x)\\\\f(2/x)=2/(2/x)\\\\f(g(x))=2x/2\\\\f(g(x))=x\\\\$

and since f(x)=g(x) the same process applies to g(f(x))

4 0

3 years ago

Find the missing sides.

love history [14]

Answer:

Part 3)

$x=6\ units$

$y=3\ units$

Part 4) $x=18\sqrt{2}\ units$

Step-by-step explanation:

Part 3)

Find the value of x

In the right triangle of the figure we know that

The cosine of angle of 30 degrees is equal to the adjacent side to angle of 30 degrees divide by the hypotenuse

$cos(30\°)=\frac{3\sqrt{3}}{x}$

and remember that

$cos(30\°)=\frac{\sqrt{3}}{2}$

substitute

$\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}$

Simplify

$x=(2*3)=6\ units$

Find the value of y

In the right triangle of the figure we know that

The sine of angle of 30 degrees is equal to the opposite side to angle of 30 degrees divide by the hypotenuse

$sin(30\°)=\frac{y}{x}$

and remember that

$sin(30\°)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{y}{6}$

$y=6/2=3\ units$

Part 4) Find the value of x

Applying the Pythagoras Theorem

$x^{2} =18^{2} +18^{2} \\ \\x^{2} = 324+324\\ \\x^{2}=648\\ \\x=\sqrt{648}\ units$

Simplify

$x=18\sqrt{2}\ units$

6 0

3 years ago

Show answer in lowest terms. 3 1 /4 - 1 3/16=

SpyIntel [72]

3 - 1 = 2
1/4 - 3/16 = 4/16 - 3/16 = 1/16

answer is : 2 1/16 (in mixed number) or 33/16 (in improper fraction)

4 0

3 years ago

Write the equations of two lines that are parallel to the line 3x+6y-5=0

Alja [10]

Answer:

X+2Y=7 and 4X+8Y=19

Step-by-step explanation:

Step 1: Write the equations in the form y=mx+c, where m represents the gradient.

In this case, gradient is equal to -0.5

Step 2: Now fix arbitrary values on the equation, y=mx+c while maintaining the value of m as - 0.5

You can make endless equations

5 0

3 years ago

The function — is used to model the height of an object projected in the air, where h(t) is the height in meters and t is the ti

MissTica

The answer choice which represents the domain and range of the function h(t) as given in the task content in which case, values are rounded to the nearest hundredth is; Domain: [0, 3.85] and Range: [0, 18.05].

<h3>What are the domain and range of the function as given in the task content?</h3>

It follows from convention that the domain of a function simply refers to the set of all possible input values for that function.

Also, the range of a function is the set of all possible output values for such function.

On this note, by observing the graph in the attached image, it follows that the Domain of the function in discuss is; [0, 3.85].

While the range is the difference between the minimum and maximum height attained and can be computed as follows;

At minimum height, t = 0; hence, h(t) = 0.

At maximum height; h'(t) = 0 where h'(t) = h'(t)=-9.74t+18.75 and hence, t = 1.92.

Hence, h(1.92) = 18.05.

The range is therefore; [0, 18.05].