Answer:
C. 30f^5
Step-by-step explanation:
5.6 f^7+(-2)
30f^5
Answer:
t = .64sec and t = 1.56sec
Step-by-step explanation:
This is motion that is modeled by a parabola. The nature of a parabola is symmtrical about some vetical line. That means that if there is an x value where y = 3, for example, when the object is traveling upwards, it will come down after it reaches its max height and be at that same y = 3 height, just at a later time. By this, I mean that you will have 2 times where the height is 7. Besides that, this is a second degree polynomial, so we are expecting 2 values of t.
We are asked to find these 2 times when the height, h, is 7. So we will fill in a 7 for h and factor to solve for t:
To factor this quadratic, we need to get everything on one side of the equals sign and set it equal to 0:
Factor this however your teacher has instructed you to factor quadratics (my guess is that you're probably using the quadratic formula) to get t values of:
t = .64 sec and t = 1.56 sec
Answer:
x=-4
x=-5
Step-by-step explanation:
Answer:
The answer is y = -1.2
Step-by-step explanation:
You can solve this by simply adding 0.6 to both sides of the equation.
y - 0.6 = -1.8
y = -1.2
Answer:
y = -6/5x - 8
Step-by-step explanation:
Use the slope-intercept form y = mx + b and substitute slope(m) = -6/5 and the point (-5, -2). After that solve for b
y = mx + b
-2 = -6/5(-5) + b
-2 = 6 + b
-8 = b
For the equation substitute into y = mx + b ; y = -6/5x - 8