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Rainbow [258]
3 years ago
13

in the evenings jake and his friends would cookout and make smores for dessert. the ratio of chocolate squares to graham cracker

s that they used is shown in the graph below.
Mathematics
1 answer:
OverLord2011 [107]3 years ago
4 0

there is no graph :l

Step-by-step explanation:

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The smaller the standard deviation, _______________________. Select one: a. the less variability it has b. the more variability
algol13

Answer:

a. the less variability it has

Step-by-step explanation:

The standard deviation is a measure of the amount of variation or dispersion of a set of values.

When your standard deviation is big your data is more dispersed.

When your standar deviation is small your mean is a representative index of your data, and there is less variability.

If there was no dispersion of the data (if all your data be the same) then the standard deviation will be 0.

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3 years ago
What is the answer to how can you use fraction strips to show that the autofoor is 7 out of 8 are not equal events
Delicious77 [7]

Answer:

The answer is B

Step-by-step explanation:

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5 0
2 years ago
Home Schoology
FrozenT [24]

Step-by-step explanation:

there are 35 in total.

4 go into one box.

so, how many in 8 boxes ?

well, 4×8 = 32

what is the difference between 32 and 35 ?

35 - 32 = 3

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4 0
2 years ago
The length of XY the minor arc is 48 cm what is the circumference of Z
Amanda [17]
If found the image that accompanies this problem, the central angle was 60°. Since the circumference of a circle is always 360°, the minor arc represents 60°/360° of the circle.

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4 0
3 years ago
Read 2 more answers
Evaluate the summation from n equals 1 to infinity of the quotient of 3 and 2 raised the quantity n minus 1 power
Shalnov [3]

Answer:

3*∑ (1/2)^n = 6

Step-by-step explanation:

We have the summation from n = 1 to n = ∞, for:

∑ 3/(2)^(n - 1)

We know that the summation between k = 0, and k = N - 1 for:

∑ r^k = (1 - r^N)/(1 - r)

if we have the summation between k = 0 and k = ∞ - 1 = ∞

(here we used that ∞ is really big, then ∞ - 1 = ∞)

In the numerator we will have the term r^∞, if 0 < r < 1, then r^∞ = 0.

Then if we assume that 0 < r < 1 we can write:

∑ r^k =  1/(1 - r)

In our case, we can rewrite our summation as:

3*∑ (1/2)^n

for n = 0 to  n = ∞

You can see that i changed the limits for n, this does not really matter because we are summing between a number and infinity, the only thing you need to take care is that now the power is n, instead of (n - 1)

Then we have r = (1/2) which is clearly smaller than 1.

then (1/2)

Then this summation is equal to:

3*∑ (1/2)^n = 3*( 1/(1 - 1/2)) = 3*( 1/( 2/2 - 1/2)) = 3*( 1/(1/2)) = 3*2 = 6

3*∑ (1/2)^n = 6

5 0
3 years ago
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