Step-by-step explanation:
Let us consider the task to find the angle between vectors ES and EJ (the first letters are taken to name the vectors).
\overrightarrow{ES} = (4;4) - (4; -3) = \overrightarrow{(0; 7)}
ES
=(4;4)−(4;−3)=
(0;7)
\overrightarrow{EJ} = (-5; -4) - (4; -3) = \overrightarrow{(-9; -1)}
EJ
=(−5;−4)−(4;−3)=
(−9;−1)
cos \alpha=\frac{\overrightarrow{ES}*\overrightarrow{EJ}}{|\overrightarrow{EJ}|*|\overrightarrow{ES}|}cosα=
∣
EJ
∣∗∣
ES
∣
ES
∗
EJ
cos(a) = (0*(-9)+7*(-1)) / (7*9.055) = -0.11043;
a = 96,34°
Solution: 96 degrees.
Answer:
Umm what
Step-by-step explanation:
Answer:
I think it's systamatic. I'm not completely sure sorry
Step-by-step explanation:
Answer:
-5+32=27
Step-by-step explanation:
-5+32=27
Hope I helped!
Let it be for x miles.
40+15+0.25x=45+0.35x
10 =0.1x
x=100
The mile is 45+0.35*100= 80 or 40+15+0.25*100 =80
