Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
The correct answer to your problem is B.
y-4 = 3(x-2)
Answer:
2x² + 6x - 4
Step-by-step explanation:
f(x) - g(x)
= 3x² + x - 3 - (x² - 5x + 1) ← distribute
= 3x² + x - 3 - x² + 5x - 1 ← collect like terms
= 2x² + 6x - 4
The equivalent is 2.45 because 147/60 = 2 27/60 and 27/60 = .45
Answer:
20 square units
Step-by-step explanation:
Area = 1/2 * base * height
Area = 1/2 * 10 * 4
Area = 20 sqaure units
