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riadik2000 [5.3K]
3 years ago
13

You were born, your mother deposited 2000 in an account that pays 5% simple interest. How much would the balance be in your acco

unt when you enter college 18 years after?
A. 18000
B. 1800
C. 3800
D. 20000
Mathematics
1 answer:
leonid [27]3 years ago
8 0

Answer:

C

Step-by-step explanation:

the formula for simple interest is given as A=P(1+rt), where A is the final balance, P is the initial principal balance (the amount of money that you start out with), r is the annual interest rate, and t is the time

we know that the mom deposited 2000 into an account when the person was born. This is our initial principal balance (the amount of money started out with)

substitute that value into the formula to get:

A=2000(1+rt)

we also know the rate, which is 5% and the time, which is 18

5%=0.05 (we need it as a decimal)

so substituting the values into the equation:

A=2000(1+0.05*18)

A=2000(1+0.9)

A=2000(1.9)

A=3,800

therefore the answer is C

Hope this helps!

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Write an equation, and solve. Round your answer to the nearest cent.
VashaNatasha [74]

Answer:

The cost of 16 oz of granola should be $16.16

Step-by-step explanation:

Given that,

The cost of 3 oz of granola is $3.03

We need to find the cost of 16 oz of granola..

As 3 oz = $3.03

1 oz = (3.03/3) = $1.01

The cost of 16 oz will be :

16 oz = 16×1.01

= $16.16

Hence, the cost of 16 oz of granola should be $16.16.

3 0
3 years ago
14 - 2 ( 1+2)<br><br> answer
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That would be 8. first parenthesis, then multiply, then subtract.
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3 years ago
Read 2 more answers
3(2x+1) =-5-5+3x solve the problem ​
Firlakuza [10]

Answer:-3

Step-by-step explanation:

8 0
3 years ago
The French Club is sponsoring a bake sale. If their goal is to raise at least $140, how many pastries must they sell at $3.50 ea
weeeeeb [17]

Let x be the number of pastries they must sell.

$3.50x≥140

This inequality states that for the number of pastries at 3.50 dollars each must be greater than or equal to 140. Solve for x.

3 0
3 years ago
According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0
3 years ago
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