<span>Use the order of operation, PEMDAS.
6²÷2(3) +4
36/2(3)+4
=(18)(3)+4
=54+4
=58</span>
Start from the parent function 
In the first case, you are computing
In the second case, you are computing
![f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)](https://tex.z-dn.net/?f=%20f%28x%2B1%29-2%20%2Ftex%5D%3C%2Fp%3E%20%3Cp%3EThere%20are%20two%20translation%20going%20on%3A%20when%20you%20transform%20%5Btex%5D%20f%28x%29%20%5Cto%20f%28x%2Bk%29%20)
, you translate the function horizontally, 
units left if 
and units right if 
.
On the other hand, when you transform 
, you translate the function vertically, units up if and units down if .
So, the first function is the "original" parabola , translated 
units right and 
units up. Likewise, the second function is the "original" parabola , translated 
units left and 
units down.
So, the transformation from 
to 
is: go 
units to the left and units down
A) The domain remains the same.
Since, in y = - 2 f(x) , the y is whats being multiplied and therefore changed, not the x or domain.
Therefore D[-6,10] <span>
The range is what changes by a factor of -2.
If the original range was [-8,12], then the new one is
[(-8 x -2),(12 x -2)] = [16 , -24].
However, you must flip the numbers to make the interval true, giving you R [-24,16]</span>
Answer:
4:10
Step-by-step explanation:
use ratio and further divide
It’s a ! you add both of the numbers to get your missing perimeter.
I’m very sorry if it’s wrong but this is what I believe! stay safe
