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d1i1m1o1n [39]
3 years ago
10

I NEED HELP QUICK! THIS IS DUE BY 5PM!!

Mathematics
2 answers:
hoa [83]3 years ago
5 0
(6x-5)2 here is the answer
skad [1K]3 years ago
3 0

Answer:

Answer for number 2 is (6x-5)2

Just looking at this makes my head ache lol .. all I could answer was number 2 sorry

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an ice skating competition lasted three days day one had an attendance of 16,390 people day two had and attendance of 16,550 peo
Jet001 [13]
Day 3 had least attendance
day 1 had middle
day 2 had most attendance

hope this helps
8 0
3 years ago
Hi, can you help me answer this question please, thank you!
pychu [463]

Okay, here we have this:

4 0
1 year ago
A recipe for oatmeal cookies makes 24 cookies. The recipe calls for 2 1/2 cups of flour. Penny wants to make 3/4 of the recipe.
barxatty [35]

Answer:

Penny needs 1\frac{7}{8} cups of flour to make 3/4 of the recipe.

The recipe will make 18 cookies.

Step-by-step explanation:

We have been given that a recipe for oatmeal cookies makes 24 cookies. Penny wants to make 3/4 of the recipe.

To find the number of cookies that will 3/4 of the recipe will make, we need to find 3/4 of 24 as shown below:

\frac{3}{4}\text{ of recipe}=24\times \frac{3}{4}

\frac{3}{4}\text{ of recipe}=6\times \frac{3}{1}

\frac{3}{4}\text{ of recipe}=18

Therefore, the recipe will make 18 cookies.

We are also told that recipe calls for 2 1/2 cups of flour. To find amount of flour needed for 3/4 of the recipe, we will multiply 2 1/2 cups by 3/4 as:

\text{Cups of flour needed to make 3/4 of recipe}=2\frac{1}{2}\times \frac{3}{4}

\text{Cups of flour needed to make 3/4 of recipe}=\frac{5}{2}\times \frac{3}{4}

\text{Cups of flour needed to make 3/4 of recipe}=\frac{5\times 3}{2\times 4}

\text{Cups of flour needed to make 3/4 of recipe}=\frac{15}{8}

\text{Cups of flour needed to make 3/4 of recipe}=1\frac{7}{8}

Therefore, Penny needs 1\frac{7}{8} cups of flour to make 3/4 of the recipe.

7 0
3 years ago
PLSS HELP ILL GIVE YOU A BRAINLIEST AND 30 points!
jekas [21]
A :-) 1.) Given - base = 9 cm
height ( alt ) = 12 cm
hypotenuse ( hypo ) = x
Solution -
By Pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 12 ) ^2
( x )^2 = 81 + 144
( x )^2 = 225
( x ) = _/225
( x ) = 15 cm

.:. The value of x ( hypotenuse ) = 15 cm


2.) Given - base = 10 cm
Height = 24 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 24 )^2
( x )^2 = 100 + 576
( x )^2 = 676
( x ) = _/676
( x ) = 26

.:. The value of x ( hypotenuse ) = 26 cm


3.) Given - base = 3 cm
Height = 7 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 3 )^2 + ( 7 )^2
( x )^2 = 9 + 49
( x )^2 = 58
( x ) = _/58
( x ) = 7.6

.:. The value of x ( hypotenuse ) = 7.6 cm


4.) Given - base = 10 cm
Height = 6 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( Hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 6 )^2
( x )^2 = 100 + 36
( x )^2 = 136
( x ) = _/136
( x ) = 11.6

.:. The value of x ( hypotenuse ) = 11.6 cm


5.) Given - hypotenuse = 24 cm
height = 6 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 24 )^2 = ( x )^2 + ( 6 )^2
( x )^2 = ( 6 )^2 - ( 24 )^2
( x )^2 = 36 - 576
( x )^2 = -540
( x ) = _/-540
( x ) = 23.2

.:. The value of x ( base ) = 23.2 cm


6.) Given - base = 1 cm
height = 1 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 1 )^2 + ( 1 )^2
( x )^2 = 1 + 1
( x )^2 = 2
( x ) = _/2
( x ) = 1.4

.:. The value of x ( hypotenuse ) = 1.4 cm


7.) Given - hypotenuse = 21 cm
height = 8 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 21 )^2 = ( x )^2 + ( 8 )^2
441 = ( x )^2 + 64
( x )^2 = 64 - 441
( x )^2 = -377
( x ) = _/-377
( x ) = 19.4

.:. The value of x ( base ) = 19.4


8.) given - height = 24 cm
Hypotenuse = 30cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 30 )^2 = ( x )^2 + ( 24 )^2
900 = ( x )^2 + 576
( x )^2 = 576 - 900
( x )^2 = -324
( x ) = _/-324
( x ) = 18

.:. The value of x ( base ) = 18 cm


9.) ( i ) lets find ‘x’
Given - base = 9 cm
height = 5 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 5 )^2
( x )^2 = 81 +25
( x )^2 = 106
( x ) = _/106
( x ) = 10.2

.:. The value of x ( hypotenuse )
= 10.2 cm

( ii ) lets find ‘y’
Given - base = 3 cm
height = 5 cm
Hypotenuse = y
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( y )^2 = ( 3 )^2 + ( 5 )^2
( y )^2 = 9 + 25
( y )^2 = 34
( y ) = _/34
( y ) = 5.8

.:. The value of y ( hypotenuse )
= 5.8 cm

4 0
3 years ago
Is the area is 49 what is the radius and diameter of the circle
Sholpan [36]

Answer:

≈ 7.80

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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