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Taya2010 [7]
3 years ago
7

Bye guys take some points its my last day

Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

B. 2

Step-by-step explanation:

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The perimeter of a triangle is 110 inches. The ratio of the side measures are 6:7:9. Find the measure of each side.
erastova [34]

The ratio of the side measures are 6:7:9.

Let's assume length of three sides of the triangle is 6x, 7x and 9x.

Given,perimeter of a triangle is 110 inches.. Perimeter is the sum of all three sides of the triangle. So, we can set up an equation as follows:

6x+7x+9x= 110

22x =110

\frac{22x}{22} =\frac{110}{22} Dividing each sides by 22.

x=5.

Now we can plug in x=5 in all the expressions of sides.

So, 6x=6(5)=30,

7x=7(5)=35

9x=9(5)=45.

So, the sides of the triangle are 30 inches, 35 inches and 45 inches.

4 0
3 years ago
Find the area of the irregular polygon?
Oksi-84 [34.3K]

Answer:

4 x 12 = 48, 48 divided by 2 = 24

8 x 12 = 96

96 + 24 = 120 ft^2

5 0
3 years ago
Read 2 more answers
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
3 years ago
What is the 20th term of 64,67,70,73,76
PIT_PIT [208]

Let's analyze the increments for each step of the sequence:

Each step we add 3 to the previous number.

Since we need the 20th, from what we saw, in the 20th term we will have added three 20 times.

So the procedure is: calculate how much is 3 times 20 and then add that to the first term of the sequence.

3\times20=60

So we add 60 to the first term to find the 20th term:

64+60=124

Answer: 124

6 0
1 year ago
What is the multiplicity of the zero of the polynomial function f(x)=(x+5)^4
iVinArrow [24]
Multiplicity would be 4
3 0
3 years ago
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