Answer:
0.48
Step-by-step explanation:
First of all. let's recall probability formula needed for solving the problem.
We know that, If the events A and B are not mutually exclusive, the probability is:
<em>probability of event (A or B) = probability of event A + probability of event B – p(A and B). </em>
This formula will be used in calculations of this problem.
Let's consider that event A is patient visiting physical therapist; event B is patient visiting chiropractor.
P (A∩B) = 0.22 (visiting both physical therapist and chiropractor) ⇔ p(A and B)
P(B) = P(A) + 0.14 [ Probability patient visiting chiropractor is 0.14 more than probability visiting physical therapist]
Patients visiting none of these is 12%
Those who visit either therapist or chiropractor are amount to 1 - 0.12 = 0.88
Now we should use the formula mentioned in the beginning of the text:
0.88 = P(A) + P(B) - 0.22 ⇒ P(A) + P(B) = 1.1
If we replace P(B) by P(A) + 0.14 ⇒ 2P(A) + 0.14 = 1.1 ⇒ 2P(A) = 1.1 - 0.14 = 0.96
So, P(A) = 0.96/2 = 0.48 [Probability of patients visiting therapist]
