Answer:
4512 handshakes
Step-by-step explanation:
We are told in the question, that there are
96 people in the room = 48 couples
Assuming that no husband or wife shakes each others hand but everyone else shakes hands exactly once
This means
48 couples will shake 94 people because they are excluded
This is calculated as
48 × 94 = 4512 handshakes
Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
Answer:
3.8%
Step-by-step explanation:
90/2358=0.038
If he flipped the coin 100 times and got 50 heads, then the answer would be 0.5 (since 50/100 = 1/2 = 0.5). I think you might be mixing theoretical probability with empirical probability.
In this case, he got 28 heads out of 75 flips
so 28/75 = 0.373333... where the 3's repeat forever
This rounds to 0.37
That's why the answer is actually choice A
