3.) 5x-6=0, Add 6 to either side -> 5x=6, divide each side by 5 -> x=6/5 ---- 4.) x+y/3=5, multiple each side by 3 -> x+y=15, move y to the other side -> x=-y+15
If

, then angle

is obtuse and triangle with sides a, b, c is obtuse triangle.
In an arbitrary triangle can be only one obtuse angle, and the side which lies opposite to the largest angle is the largest. Then since <span>angle

is opposite the side of length a</span> you can conclude that a>c and a>b.
Step-by-step explanation:
let both unknowns be x and y
x = 5y. ......(1)
x + y = 90. ......(2)
sub eqn (1) into eqn (2)
5y + y = 90
6y = 90
y = 90/6
= 15
sub y = 15 to eqn (1)
x = 5y
x = 5 × 15
× = 75
Answer: -3
Step-by-step explanation:
18/6 = 3
18/-6 = -3