The denominator : q² - 3q - 4 should be ≠ 0.
Let's find the zero values of this quadratic equation:
q' = [-b+√(b²-4.a.c)]/2.a and q'' = [-b-√(b<span>²-4.a.c)]/2.a
you will fond q' = 4 and q'' = -1
Then the restrictions are :
q </span>≠ 4 and q ≠ - 1 (1st answer)
Answer:
11
Step-by-step explanation:
|11| is a module, the numbers inside a module are equal to positive ones so
|11| and |-11| are both equal to 11
The quick way to get the answer is just type "42 choose 11" into Google.
Or if you want to figure it out yourself, you have 42 choices for the first potential juror, 41 choices for the second potential juror, etc.
Now before you stop there, you only care about the combination of the 11 people chosen, not what order they are selected, so you need to divide by the ways to arrange 11 people.
Final expression:
C(42,11) = (42 * 41 * 40 * 39 * 38 * 37 * 36 * 35 * 34 * 33 * 32) / (11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)
Answers:
4,280,561,376 ways
Answer:
She can invite 109 guests and be right on top of budget. If she wants to spend less than her budget though she can only invite 108 people.
Step-by-step explanation:
First you have to subtract 5,748 - 2,478 which is 3270. Next you have to divide 3270 by 30 because each person costs 30 dollars. 3270 divided by 30 is 109.
I hope this helps! Please mark me brainliest if I am correct! Have a nice day!
Answer:
-17
Step-by-step explanation:
-16r=272
16r=-272
r=-17
