Answer:
The frequency does not change with more trials
Step-by-step explanation:
To predict: the probability of the coin landing heads up
Solution:
Probability refers to the chances that an event will occur in an experiment. The value of probability lies between 0 and 1. 0 indicates impossible event and 1 indicates a sure event. The probability of an event can not be greater than 1.
When a coin is tossed, there are two possible outcomes: heads (H), tails (T).
In case of the probability of the coin landing heads up, the frequency does not change with more trials.
Answer:
It can't be C or D. I think it could be A.
<h3>
Answer: -13</h3>
=======================================
Explanation:
g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)
g(1) = -4 means we have the point (1,-4)
Find the slope of the line through the two points (-3,2) and (1,-4)
m = (y2-y1)/(x2-x1)
m = (-4-2)/(1-(-3))
m = (-4-2)/(1+3)
m = -6/4
m = -3/2
m = -1.5
The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5
Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation: 2 = -1.5*(-3) + b
Let's solve for b
2 = -1.5*(-3)+b
2 = 4.5 + b
2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides
-2.5 = b
b = -2.5
Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5
The last step is to plug in x = 7 and compute
g(x) = -1.5*x - 2.5
g(7) = -1.5*7 - 2.5
g(7) = -10.5 - 2.5
g(7) = -13
Are you sure you want ONLY the coefficient of b? If you expand this, you will have b in 3 of 4 terms.
According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:
1
1 2 1
1 3 3 1
1 4 6 4 1
So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4
Here, you want (3 + b)^4. Here's what that looks like:
3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]
Which coeff did you want?
