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3 years ago

3=2/6*4+b solve for b

Mathematics

2 answers:

defon3 years ago

7 0

Answer:

1 2/3

Step-by-step explanation:

If you do the things in the order which would be 2/6*4 (because that is how the order of operations would be) that equals 1 1/3 in fractions. So to get to B, you need to find what equals 3 so you would do 3- 1 1/3 and that would give you 1 2/3.

cricket20 [7]3 years ago

7 0

3=2/6*4+b

3=4/3+b

3-4/3=b

B=2 2/3

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In an aquarium 2/5 of the fish or surgeonfish. Of these, 3/4 are yellow tangs. what fraction of all fish in the aquarium or yell

Viktor [21]

Answer:

3/10 of the aquarium are yellow tangs.

Step-by-step explanation:

Given that in an aquarium 2/5 of the fish or surgeonfish and of these, 3/4 are yellow tangs, to determine what fraction of all fish in the aquarium are yellow tangs the following calculation must be performed:

2/5 = 0.40

0.40 x 3/4 = X

1.20 / 4 = X

0.30 = X

0.30 = 3/10

Therefore 3/10 of the aquarium are yellow tangs.

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3 years ago

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I believe it is A correct me if I’m wrong

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3 years ago

In your own words, explain why C=2πr, where C is the circumference of a circle of radius r. Include a description of the number

schepotkina [342]

Answer:

Pi—which is written as the Greek letter for p, or π—is the ratio of the circumference of any circle to the diameter of that circle. Regardless of the circle's size, this ratio will always equal pi(3.1415).

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Step-by-step explanation:

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3 years ago

Your neighbor has a square shaped pool with side lengths of 3a5. What is the area of the pool?

velikii [3]

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3 years ago

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago