Answer:
e^ln 1 = 1
e^ln 5x = 5x ,where x > 0
I think you mean Mean Absolute Deviation or MAD. It means the average amount the digits are from the mean, so let's say the mean is 4 and the digits are 2, 6, 4. So find the difference of each digit 4-2=2 6-4=2 and 4-4=0. So you have 2, 2, 0. Now find the mean of those 3 numbers which will be 4/3.
Let H = Hailey, M = Megan, B = Bailey
H + M + B = 458
167 + M + B = 458
M + B = 291
152 ≤ M ≤ 164
If M = 152, B = 139
If M = 164, B = 127
Thus,
$127 ≤ B ≤ 139
Answer: solutions found
Step by Step Solution
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Reformatting the input :
Changes made to your input should not affect the solution:
(1): "u2" was replaced by "u^2". 2 more similar replacement(s).
Non Integer Exponent Not Yet Implemented
........ V
(x^3x^u^2032+3x-2)0x-2;ox+2;ox-4ox+1;(*^u^2032-x+1)
Non Integer Exponent Not Yet Implemented
.......................................... V
(x^3x^u^2032+3x-2)0x-2;ox+2;ox-4ox+1;(*^u^2032-x+1)
Consecutive Operators
................................................ V
(x^3*x^u^2032+3*x-2)0*x-2;o*x+2;o*x-4*o*x+1;(*^u^2032-x+1)
Program Execution Terminated
Tiger was not able to solve for your input:(x3x^u2032+3x-2)0x-2;ox+2;ox-4ox+1;(*^u2032-x+1)
Step-by-step explanation:
Answer:
the answer is (8,5)
Step-by-step explanation:
idk how to expalin it lol so i hope its correct
