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STatiana [176]
3 years ago
9

PLEASE HELP ASAP.

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

Answer:

x=13

m∠A = 46°     m∠B = m∠C = 67°

Step-by-step explanation:

ΔABC : isosceles    

vertex ∠A = 4x -6

∠B = ∠C = 5x + 2

∠A + ∠B + ∠C = 180° = (4x -6) + 2 * (5x + 2) = 14x - 2

14x = 182       x = 13

∠A = 46°     ∠B = ∠C = 67°

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Find f-1(x), if f(x) = 3x – 6. Justify your
Sergio039 [100]
Answer: 1/3 (x + 6)

Explanation: given f(x) = 3x - 6.
Let y = f(x) and so y = 3x - 6.
Trade places between x and y.
x = 3y - 6
Solve for y
x + 6 = 3y
y = x + 6/3
Now the new y is the inverse and so y = f-1(x)
f-1(x) = 1/3(x + 6)
4 0
3 years ago
A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

8 0
3 years ago
If m<9=97 and m<12=114, find each measure.
seropon [69]

Answer:

a. 97

b. 83

c.66

d. 114

e.83

f. 97

g. 114

h.66

i. 83

j. 66

k.83

l.97

m. 114

n. 66

6 0
3 years ago
F m 1=7x and m 4=3x+20 what is the m 2
djyliett [7]
M2=5x+10
.................
4 0
3 years ago
Convert the complex number z = -12 + 5i from rectangular form to polar form.​
Paha777 [63]

Answer:

z=13(\cos 157\degree +i\sin157\degree)

Step-by-step explanation:

The given complex number is

z=-12+5i

The polar form of this complex number is;

z=r(\cos \theta +i\sin \theta), where

r=\sqrt{(-12)^2+5^2}

r=\sqrt{144+25}=\sqrt{169}=13

and

\theta =\tan^{-1}(\frac{5}{-12})

This implies that;

\theta=157\degree to the nearest degree.

Hence the polar form is

z=13(\cos 157\degree +i\sin157\degree)

7 0
4 years ago
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