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aivan3 [116]
4 years ago
5

Find the x-intercept of the graph of the linear equation y = - 2 x + 3.

Mathematics
1 answer:
Lina20 [59]4 years ago
3 0
The answer is y= -6.
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Which equation in point-slope form contains the point (–3, 5) and has slope –1? y + 3 = –1(x – 5) y – 5 = –1(x + 3) y – 3 = –1(x
andreev551 [17]

Answer:

y - 5 = -1(x + 3)

Step-by-step explanation:

Point slope form

y - y1 = m(x - x1) where m = slope and passing through point (x1 , y1)

In this case if the equation in point-slope form contains the point (–3, 5) and has slope –1 then the equation should be:

y - 5 = -1(x - (-3))

y - 5 = -1(x + 3)

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Johan ran 36.25 miles in 5 hours. How many miles did he run every hour?
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3 years ago
Expres each of the folowing as a single matrix.
Elden [556K]

Answer:

\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]

Step-by-step explanation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]

We have:

A=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]\\and\\B=\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]

And we need to express as a single matrix:

A+B=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6+(-2)&-3+8\\10+3&-1+(-12)\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6-2&5\\13&-1-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]

The answer is:

\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]

It is expressed as a single matrix.

8 0
3 years ago
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