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3 years ago

Identify which triangles are congruent, and explain your answer.

Mathematics

2 answers:

Paha777 [63]3 years ago

7 0

I believe that A and D would be the correct answer. Because both are 30,60,90 triangles and would be congruent. The other 2 triangles only have 1 angle and their side measures are at two different places meaning they cannot be congruent.

Marina86 [1]3 years ago

6 0

This is a 30-60-90 triangle. Following the pattern of x, $x \sqrt{3}$ , and 2x. So lets us look for that pattern in these triagles.
Judging from what I know, the answer is A and C.
They hypotenuse is 2 times the shorter leg, which is evident here. B and D are incorrect, since if the longer leg is 18, then the smaller leg would be a large square root , possibly a number in the mid 500s being squared.
Hope this helps

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Mary is four years older than Sue. If the sum of their ages is 16, how old are Mary and Sue?

dusya [7]

Answer:

Sue is 6 and Mary is 10

Step-by-step explanation:

let Sue's age be x then Mary is x + 4 and the sum of their ages is

x + x + 4 = 16

2x + 4 = 16 ( subtract 4 from both sides )

2x = 12 ( divide both sides by 2 )

x = 6

x + 4 = 6 + 4 = 10

then Mary is 10 and Sue is 6

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1 year ago

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Find all solutions in the region [0,2pi) for the equation cos^2(2x)-sin^2(2x)=0

Lynna [10]

$\cos^{2}(2x)-\sin^{2}(2x)=0$
$\rightarrow \sin^{2}(2x)=\cos^{2}(2x)$
$\rightarrow \frac{\sin^{2}(2x)}{\cos^{2}(2x)}=1$
$\rightarrow \tan^{2}(2x)=1$
$\rightarrow \tan(2x)=\pm 1$

$2x$ can range anywhere in $[0, 4\pi)$
So:
$\rightarrow 2x=\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}, \frac{9\pi}{4}, \frac{11\pi}{4}, \frac{13\pi}{4}, \frac{15\pi}{4}$
$\rightarrow x=\frac{\pi}{8}, \frac{3\pi}{8}, \frac{5\pi}{8}, \frac{7\pi}{8}, \frac{9\pi}{8}, \frac{11\pi}{8}, \frac{13\pi}{8}, \frac{15\pi}{8}$

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3 years ago

For what value of k does the equation 6(x + 1) + 2 = 3(k5x + 1) + 3 have no solution?

NARA [144]

Answer:

k = (6/15)

Step-by-step explanation:

The equation is:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

To have no solutions, we need to have something like:

x + 7 = x + 4

where we can remove x in both sides and end with

7 = 4

So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.

First, let's try to simplify our equation:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

6*x + 6 + 2 = 3*k*5*x + 3*1 + 3

6*x + 8 = 15*k*x + 6

if 15*k = 6, then the system clerly has no solution.

then:

k = 6/15

then we get:

6*x + 8 = (6/15)*15*x + 6

6*x + 8 = 6*x + 6

8 = 6

The system has no solutions.

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