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Anon25 [30]
3 years ago
7

Surface area formula of a parallelogram prism

Mathematics
1 answer:
Alina [70]3 years ago
8 0
SA=bh (surface area for parallelogram prism)
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Answer PLEASE zoom in the photo to see
Slav-nsk [51]

Answer:

B

Step-by-step explanation:

20*3=60

20*7=140

20*11=220

8 0
3 years ago
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Solve for x with 45 degree angle & 60ft side
Alona [7]

Answer:

x = 84.85281374 ft

Step-by-step explanation:

We know that sin theta = opposite/ hypotenuse

sin 45 = 60/x

Multiply each side by x

x * sin45 = 60/x*x

x sin 45 = 60

Divide each side by sin 45

x = 60/sin 45

x = 84.85281374 ft

5 0
3 years ago
On a piece of paper, use a protractor to construct a triangle with angle measures of 100° and 30°.
yanalaym [24]

The third angle measures 50° and all sides have different lengths.

<h3>What is a triangle?</h3>

A triangle is a polygon with three sides and three angles. Types of triangles are<em> isosceles, equilateral, scalene and right angled.</em>

The sum of angles in a triangle is 180 degrees.

A triangle with angle measures of 100° and 30°, let x represent the third angle, hence:

x + 100 + 30 = 180° (sum of angles in a triangle)

x = 50°

Also, all sides have different lengths since all the angles are different.

Find out more on triangle at: brainly.com/question/2644832

8 0
3 years ago
A plant is already 13.25 meters tall, and it will grow 9 centimeters every month. The plant's height, H (in meters), after x mon
7nadin3 [17]

H = 0.09 (20) + 13.25

H = 1.80 + 13.25

H = 15.05 m

8 0
2 years ago
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0 A two-inch-long grasshopper can jump a horizontal distance of 40 inches. An athlete, who is _ five feet nine, wants to cover a
Mkey [24]

Answer:

a) nearest jump is JL = 1380 inches = 115ft

b) number of jumps in 1 mile N= 46 jumps

Step-by-step explanation:

Given that the jump length is proportional to the body length.

If 2 inch grasshopper can jump 40 inches.

JL = k(BL)

k = JL/BL

where JL = jump length = 40 inches

BL = Body length = 2 inches.

k = 40/2 = 20

The constant of proportionality is 20.

For the athlete :

BL = 5ft 9 inches = 5(12)+9 = 69 inches.

The jump length of the athlete is:

JL = k(BL) = 20(69)

JL = 1380 inches. = 115ft

The number of jumps in 1 mile is

1 mile = 63360 inches

N = 63360/1380

N = 45.9 = 46

N= 46

Therefore, 46 jumps would be needed.

7 0
3 years ago
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