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Levart [38]
3 years ago
13

Please answer the questions in my profile. There's plenty of points there

Mathematics
1 answer:
Shtirlitz [24]3 years ago
3 0

Answer:

ok

Step-by-step explanation:

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Factor x^4 + x y^3 + x^3 + y^3 completely. Show your work.
andrey2020 [161]
\bf x^4+xy^3+x^3+y^3\impliedby \textit{now let's do some grouping}
\\\\\\
(x^4+xy^3)~~+~~(x^3+y^3)\implies x(x^3+y^3)~~+~~(x^3+y^3)
\\\\\\
\stackrel{\stackrel{common}{factor}}{(x^3+y^3)}(x+1)\\\\
-------------------------------\\\\
\textit{now recall that }\qquad \qquad \textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
a^3-b^3 = (a-b)(a^2+ab+b^2)\\\\
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(x+y)(x^2-xy+y^2)(x+1)
5 0
3 years ago
16. Adam uses a microscope to observe insects in science class. The
Deffense [45]

Answer:

A= 0.5, B=2.2, C=0.12, D=.0.9.

Step-by-step explanation:

5 0
3 years ago
Use the Rational Zeros Theorem to write a list of all potential rational zeros. f(x) = x3 - 5x2 + 8x - 24
masha68 [24]
If I remember correctly this would be  obtained from the factors of  -24

so i think its +/-1, +/-2, +/- 3, +/- 4, +/- 8, +/- 6 , +/-12, +/-24

Sorry but i cant be sure
6 0
3 years ago
Read 2 more answers
Help me do question 9 and 10 I am 6th grade. Please
Phoenix [80]

Answer:

Step-by-step explanation:

9 - ratio 3:5

10 1/8 + 1/4 = 1/8 + 2/8 = 3/8 of the pizza eaten

so 5/8th of the pizza is left

8 0
3 years ago
Find two numbers whose sum is 25 and the sum of whose reciprocals is 1/6
Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

y2 = 10

Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

5 0
3 years ago
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