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djyliett [7]
3 years ago
5

Find the slope of the line going through the points (-4, 3) and (-1,-6)

Mathematics
2 answers:
Fed [463]3 years ago
8 0

Answer:

-3

Step-by-step explanation:

m=y2-y1/x2-x1

m=-6-3/-1-(-4)

m=-9/3

m=-3

Anuta_ua [19.1K]3 years ago
5 0

Answer:

\big \: slope =  - 3

Step-by-step explanation:

\boxed {slope =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} }

HERE,

slope =  \frac{( - 6) - 3}{( - 1) - ( - 4)}

=   \frac{ - 9}{3}

=  - 3

Therefore,

\green{\boxed { \red{ \bold{slope \:  =  - 3}}}}

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Step-by-step explanation:

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The graph of a proportional relationship passes through the point (6, 21). What is the equation for the relationship?​
Kipish [7]

Answer:

The equation for the relationship is y = \frac{7}{2}\cdot x.

Step-by-step explanation:

Given that point (x,y) = (6, 21) is part of a direct relationship. That is:

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7 0
3 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

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0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

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Step-by-step explanation:

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