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3 years ago

Solve for n. Q=5n+5z

Mathematics

2 answers:

Assoli18 [71]3 years ago

8 0

$Q=5n+5z\\
5n=Q-5z\\
n=\frac{Q-5z}{5}$

kirill115 [55]3 years ago

5 0

$q=5n+5z\ \ \ \ \ \ \ |subract\ 5z\\\\q-5z=5n\ \ \ \ \ \ \ |divide\ by\ 5\\\\n=\frac{q-5z}{5}\\\\Answer\ is\ n=\frac{q-5z}{5}$

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3 years ago

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Step-by-step explanation:

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2 years ago

A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
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We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
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$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

$A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}$

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3 years ago