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3 years ago

Find the x-intercept and y-intercept of the line. 2x-6y=6

Mathematics

2 answers:

scoundrel [369]3 years ago

5 0

Answer:

x-intercept: (3,0)

y-intercept: (0,−1)

AVprozaik [17]3 years ago

4 0

Answer:

Y Intercept: (0,-1)

X Intercept: (3,0)

Step-by-step explanation:

Let's rearrange the original equation to be in y intercept form

2x-6y=6

-6y=-2x+6 (isolate y on the left side by subtracting both sides by -2)

6y=2x-6 (we can divide both sides by -1 to eliminate the negative signs)

y=2/6x-1

the y intercept is when x = 0, so we can insert that into the new equation we have

y=2/6(0)-1

y=-1

we can also use the new formiula to find the x intercept, the x intercept is when y = 0

y=2/6x-1

0=2/6x-1

-2/6x=-1 (isolate x by subtracting both sides by 2/6x)

2/6x=1 (divide both sides by -1 again to get rid of the negative signs)

2x=6 (multiply both sides to get rid of the 6 in the denominator)

x=3 (divide both sides by 2 to isolate x)

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a_sh-v [17]

12*13*14*15*16 = 524160

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3 years ago

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AveGali [126]

Answer:

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Step-by-step explanation:

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3 years ago

What is the sign of-5×-1/-2

Svetradugi [14.3K]

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3 years ago

The coordinates of point A are (p, q) and coordinates of point B are (p+2q, q+2p). Provide your complete solutions and proofs in

Dafna1 [17]

Answer:

The mid-point (p + q , q + p) of AB is the same distance from the x-axis and the y-axis

Step-by-step explanation:

* Lets explain how to solve the problem

- Any point will be equidistant from the x-axis and the y-axis must have

equal coordinates

- Ex: point (4 , 4) is the same distance from the x-axis and the y-axis

because the distance from the x-axis to the point is 4 (y-coordinate)

and the distance from the y-axis and the point is 4 (x-coordinate)

- If (x , y) is the mid-point of a segment its endpoints are

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then

$x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

* Lets solve the problem

∵ Point A has coordinates (p , q)

∵ Point B has coordinates (p + 2q , q + 2p)

- The mid-point of AB is (x , y)

∵ $x=\frac{p+p+2q}{2}$

∴ $x=\frac{2p+2q}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $x=\frac{2(p+q)}{2}$

- Divide up and down by 2

∴ x = p + q

∵ $y=\frac{q+q+2p}{2}$

∴ $y=\frac{2q+2p}{2}$

- Take 2 as a common factor from the terms of the numerator

∴ $y=\frac{2(q+p)}{2}$

- Divide up and down by 2

∴ y = q + p

∴ The mid point of AB is (p + q , q + p)

- p + q is the same with q + p

∵ The x-coordinate of the mid point of AB is p + q

∵ The y-coordinate of the mid point of AB is q + p

∵ p + q = q + p

∴ The coordinates of the mid-point of AB are equal

- According the explanation above

∴ The mid-point (p + q , q + p) of AB is the same distance from the

x-axis and the y-axis

8 0

3 years ago

Justin is 2 years older

german

Answer:
5

Explanation:
1/4 of 12 = 3
2 + 3 = 5

5 0

3 years ago