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AnnZ [28]
3 years ago
10

PLEASE ANSWER AND HELP

Mathematics
1 answer:
ra1l [238]3 years ago
7 0
She must save $91.80.
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Use the distributive property to expand each expression. 0.5(12m - 22n) 0.5(12m - 22n =0.5(____) - 0.5(____)
lesya [120]

Answer:

0.5(_12m_) - 0.5(_22n_)

Step-by-step explanation:

To apply the distributive property multiply each the term outside to each term in the parenthesis.

0.5(12m - 22n) 0.5(12m - 22n =0.5(_12m_) - 0.5(_22n_)

5 0
3 years ago
Im in algebra II honors and right now we are working on parabolas and quadratic equations. Can someone help me understand how to
Maurinko [17]

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function.

The standard form of a parabola is y=ax2++bx+c , where a≠0 . The vertex is the minimum or maximum point of a parabola. If a>0 , the vertex is the minimum point and the parabola opens upward. If a<0 , the vertex is the maximum point and the parabola opens downward.

8 0
2 years ago
Rotations Please help me.
Trava [24]

Answer:

  see attached

Step-by-step explanation:

You can do these yourself fairly easily. Copy the figure and the coordinate axes onto a piece of tracing paper (tissue paper or even facial tissue will work, too), then rotate the copied figure 90° clockwise.

Line up the origin of the axes and make sure the axes you drew line up with the ones on the original figure. For 90° clockwise rotation, what was the +y axis will now align with the +x axis. Copy the rotated figure from the tracing paper back to the graph on your problem page in its new location. (You can cut out the figure, if necessary. Just be sure to make note of the position relative to the axes.)

This sort of physical activity reinforces the thinking you need to do to mentally rotate the figures. It is worth the effort.

7 0
2 years ago
Answer is -66 but show the work of how you got that answer
Greeley [361]

Answer:

-66

Step-by-step explanation:

P(8) = -8^2 - 2

-64 -2 =  -66

6 0
2 years ago
A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require
Aleksandr-060686 [28]

Answer:

r\approx 1.084\ feet

h\approx 1.084\ feet

\displaystyle A=11.07\ ft^2

Step-by-step explanation:

<u>Optimizing With Derivatives </u>

The procedure to optimize a function (find its maximum or minimum) consists in :

  •  Produce a function which depends on only one variable
  •  Compute the first derivative and set it equal to 0
  •  Find the values for the variable, called critical points
  •  Compute the second derivative
  •  Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 ft^3. The volume of a cylinder is given by

\displaystyle V=\pi r^2h

Equating it to 4

\displaystyle \pi r^2h=4

Let's solve for h

\displaystyle h=\frac{4}{\pi r^2}

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

\displaystyle A=\pi r^2+2\pi rh

Replacing the formula of h

\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )

Simplifying

\displaystyle A=\pi r^2+\frac{8}{r}

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

\displaystyle A'=2\pi r-\frac{8}{r^2}=0

Rearranging

\displaystyle 2\pi r=\frac{8}{r^2}

Solving for r

\displaystyle r^3=\frac{4}{\pi }

\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet

Computing h

\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

\displaystyle A''=2\pi+\frac{16}{r^3}

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.

The minimum area is

\displaystyle A=\pi(1.084)^2+\frac{8}{1.084}

\boxed{ A=11.07\ ft^2}

8 0
3 years ago
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