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Katyanochek1 [597]
3 years ago
10

1) g=-y+c/x, solve for X

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

the solution  x = \frac{c}{g-y}

Step-by-step explanation:

<u>Step 1:-</u>

Given problem g=\frac{-y+c}{x}

here l.cm is x

g = \frac{x y+c}{x}

cross multiplication we get ,

g x = x y +c

<u>Step 2</u>:-

subtracting x y on both sides , we get

g x - x y = c

taking common 'x' we get,

x(g-y) = c

<u>Final answer</u>:-

x = \frac{c}{g-y}

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3 years ago
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What number should be added to both sides of the equation to complete the square x^2+3x=6
Allisa [31]
Take half of the coefficient of x:  It is 3, and half that is 3/2.


Then   <span>x^2+3x=6  becomes:

</span><span>           x^2+3x + (3/2)^2 =6 + (3/2)^2, and

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You were not asked to solve the equation, but why not do it for the practice?

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8 0
3 years ago
Who had this before if so can I get help
telo118 [61]

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6 0
2 years ago
Percy said that any real number for k would cause the system of equations to have no solution. Explain the error in Percy’s stat
MatroZZZ [7]

Answer:

Except k=7, any real number for k would cause the system of equations to have no solution.

Step-by-step explanation:

In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.

Just for information, if k=7 the system will have infinitely many solutions.

5 0
2 years ago
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