If you have a quadratic equation in the form ax^2+bx+c
Step 1) Determine the product of AC (the coefficients in a quadratic equation)
Step 2) Determine what factors of a⋅ca⋅c sum to bb
Step 3) "ungroup" the middle term to become the sum of the factors found in step 2
Step 4) group the pairs.

3 0

3 years ago

Winston owns a coffe cart. He charges $1.50 for a cup of coffe , and it costs him $0.50 to make each cup of coffe plus $100 a da

Artist 52 [7]

100 + 0.50c = 1.50c <== ur equation
100 = 1.50c - 0.50c
100 = c....so he would have to sell 100 cups of coffee to break even

4 0

3 years ago

Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5

dolphi86 [110]

Answer:

30 $(x+1)^8 (x-4)^5$

Step-by-step explanation

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X $(x+1)^8 (x-4)^5$

30 $(x+1)^8 (x-4)^5$

7 0

3 years ago