Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
Answer:
The answer is 20.0855
Step-by-step explanation:
<u>Ca</u><u>l</u><u>c</u><u>ulate the approximate </u><u>value</u>
e³ = 20.0855
Hope this helps you
I think the answer is 4x^2 (x+6)
