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2 years ago

15

(t + 1)(t2 + 2t + 4) find the product.

2 answers:

lawyer [7]2 years ago

8 0

The answer you are looking for is t^3+3t^2+6t+4.

Solution:

(t+1)(t^2+2t+4)

t^3+2t^2+4t+t^2+2t+4

t^3+3t^2+6t+4

Fiesta28 [93]2 years ago

3 0

Answer:

5+5t

Step-by-step explanation:

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2 years ago

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madam [21]

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A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

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2 years ago

41 is 163 added to y

fomenos

Answer:

y + 163 = 41

Step-by-step explanation:

I think you are correct. It should be y + 163 = 41

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Kaylis [27]

The answer is false
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