Answer:
The radius of circle B is 6 times greater than the radius of circle A
The area of circle B is 36 times greater than the area of circle A
Step-by-step explanation:
we have
<em>Circle A</em>
The radius of circle A is
-----> the radius is half the diameter
<em>Circle B</em>
Compare the radius of both circles
The radius of circle B is six times greater than the radius of circle A
Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared
All circles are similar
In this problem the scale factor is 6
so
therefore
The area of circle B is 36 times greater than the area of circle A
It would be true that all three quadrants could be occupied
Answer:
The ratio 
represents the tangent of ∠I
Step-by-step explanation:
Let us revise the trigonometry ratio
In Δ HIJ
∵ m∠J = 90°
- Hypotenuse is the side which opposite to the right angle
∴ HI is the hypotenuse
∵ HJ = 3 units
∵ IH = 5 units
- Let us use Pythagoras Theorem to find HJ
∵ (HJ)² + (IJ)² = (IH)²
∴ 3² + (IJ)² = 5²
∴ 9 + (IJ)² = 25
- Subtract 9 from both sides
∴ (IJ)² = 16
- take √ for both sides
∴ IJ = 4 units
To find the tangent of ∠I find the opposite and adjacent sides to it
∵ HJ is opposite to ∠I
∵ IJ is adjacent to ∠I
- use the rule of tan above
∴ tan(∠I) = 
∴ tan(∠I) =
The ratio represents the tangent of ∠I
K = 16. how ? math yup yup Imma pro.
Answer:
x = 50°
2x = 100°
Step-by-step explanation:
Chords AB and DC are equidistant (3 units) from the center E of the circle.
Since, the chords equidistant from the center of the circle are congruent.
Congruent chords intercepts congruent arcs.
Hence, x = 50°
2x = 2*50° = 100°
