A system of linear inequalities can have solutions in exactly three of the quadrants
2 answers:
It would be true that all three quadrants could be occupied
Answer with explanation:
Consider the Inequality
x - y >0
⇒x > y
or, x -y < 0
⇒ x < y
It has solution in all the three regions.
Plotting the Inequality in x y plane and showing that the solution lies in three of the Quadrants
So, Yes , a system of linear inequalities can have solutions in exactly three of the quadrants.
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Answer:
25% hope this is correct
2 + 5 = 7
7 + 8 = 15
15 +11 = 26
11+3 = 14
26 + 14 = 40
so he has 5 sets
I think that is it not sure
Subtract 7 from both sides
-2m = 11 - 7
Simplify 11 - 7 to 4
-2m = 4
Divide both sides by -2
m = -4/2
Simplify 4/2 to 2
<u>m = -2</u>