What is the area for this square. (This question is related to square roots)
1 answer:
Answer:
Step-by-step explanation:
the are of the square is side*side or in your case, A=2
*2![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
A=2*2(
)=4*3=12
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Answer:
![\frac{1}{4c+5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4c%2B5%7D)
Answer: x>-9
Step-by-step explanation:
Incomplete question !!!!!!!!!
Answer: option D: eight root.Explanation:1) Expression given:
![{ (x^{3/8} )}^{z/3}](https://tex.z-dn.net/?f=%7B%20%28x%5E%7B3%2F8%7D%20%29%7D%5E%7Bz%2F3%7D%20)
2) Use
power of power property:
![{ (x^{3/8} )}^{z/3}= x^{ \frac{3}{8} \frac{z}{3} } =x^{ \frac{z}{8} }](https://tex.z-dn.net/?f=%7B%20%28x%5E%7B3%2F8%7D%20%29%7D%5E%7Bz%2F3%7D%3D%20x%5E%7B%20%5Cfrac%7B3%7D%7B8%7D%20%20%5Cfrac%7Bz%7D%7B3%7D%20%7D%20%3Dx%5E%7B%20%5Cfrac%7Bz%7D%7B8%7D%20%7D)
3) Use
fraction exponent property:
![x^{ \frac{z}{8} }= \sqrt[8]{x^z}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7Bz%7D%7B8%7D%20%7D%3D%20%5Csqrt%5B8%5D%7Bx%5Ez%7D%20)
That is an eigth root.
let log2 32 = x
then 2^x = 32
but we know 2^5 = 32
therefore, x = 5