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solniwko [45]
3 years ago
8

Helppp please as soon as possible

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

ChaptersMenu

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Video Available Video Available

4.1.4 Solved Problems:

Continuous Random Variables

Problem

Let X be a random variable with PDF given by

fX(x)={cx20|x|≤1otherwise

Find the constant c.

Find EX and Var(X).

Find P(X≥12).

Solution

Problem

Let X be a continuous random variable with PDF given by

fX(x)=12e−|x|,for all x∈R.

If Y=X2, find the CDF of Y.

Solution

First, we note that RY=[0,∞). For y∈[0,∞), we have

FY(y) =P(Y≤y)

=P(X2≤y)

=P(−y√≤X≤y√)

=∫y√−y√12e−|x|dx

=∫y√0e−xdx

=1−e−y√.

Thus,

FY(y)={1−e−y√0y≥0otherwise

Problem

Let X be a continuous random variable with PDF

fX(x)={4x300<x≤1otherwise

Find P(X≤23|X>13).

Solution

Problem

Let X be a continuous random variable with PDF

fX(x)={x2(2x+32)00<x≤1otherwise

If Y=2X+3, find Var(Y).

Solution

Problem

Let X be a positive continuous random variable. Prove that EX=∫∞0P(X≥x)dx.

Solution

Problem

Let X∼Uniform(−π2,π) and Y=sin(X). Find fY(y).

Solution

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Creative Commons License

Introduction to Probability by Hossein Pishro-Nik is licensed under a Creative Commons Attribution-NonCommercial-NoDerivs 3.0 Unported License

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Answer:

Type A coffee in lbs = 97 lbs

Step-by-step explanation:

Type a = 4.55/lbs = x

type b = 5.70/lbs =  y

Total in lbs = 147lbs

total in sales = 726.50

First,

x + y = 147 lbs    -------------------equ 1

4.55x + 5.70y = lbs    ------------ equ 2

<em>Multiply equ 1 by 4.55</em>

4.55x + 4.55y = 668.85  -------------equ 3

4.55x + 5.70y = 726.50   ------------equ 4

<em>Subtracting equ 3 from equ 4</em>

1.15y = 57.65

y = 50

<em>Substituting y = 50 into equ 1</em>

x + 50 = 147

x = 97

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3 years ago
Need help ASAP !!!!!!!!!!!!!!!!
klemol [59]

Answer:

it blury put a better one pls

Step-by-step explanation:

3 0
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swat32

The answer on E2020 is A: Rolling a six-sided number cube 24 times and recording if a 4 comes up.

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−10=2y<br><br> Hello<br><br> Help <br><br> Me
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The answer is -5

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