So this is a difference of 2 perfect squares
so if
x^2-y^2 then it is equal to (x-y)(x+y)
so
x^4-81=[(x^2)^2]-[(9)^2]=(x^2-9)(x^2+9)
so we know if xy=0 then x or/and y=0 so assume that they are equal to zero
x^2+9=0
we can't do anything about this because
x^2=-9
and that is not possible in the real realm
x^2-9=0
yet another difference of 2 perfect squares
x^2-3^2=(x-3)(x+3)=0
set them to zero
x-3=0
x=3
x+3=0
x=-3
so x=3 or -3
The given polynomial expressed as partial fraction is 5x^3 + 9/x
<h3>Polynomial function and partial fractions</h3>
Polynomial function are function that have a leading degree of 3. Given the expression below;
f(x) = (5x^4+9)/x
Applying partial fraction
Since the part fraction means separating the fraction into two parts, hence;
f(x) = 5x^4/x + 9/x
Simplify
Since there is value of x at both numerator and denominator, it will cancel out to have
f(x) = 5x^3 + 9/x
From the result, we can see that p(x) = 5x^3 and k = 9
Hence the given polynomial expressed as partial fraction is 5x^3 + 9/x
Learn more on polynomial here: brainly.com/question/2833285
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You know that the square root of 144 is 12 and 169 is 13. 150 is in between 144 and 169 so its square root must be between 12 and 13.
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Answer:
a its parallel
b its parallel
c its parallel
Step-by-step explanation:
i dont know it's about parallel
