Ask question

Ask question

All categories

andrew-mc [135]

3 years ago

8

97823843221623882623602794632621621738987345381237787733247697818473621883466325342536234347642375362374564357343525234766244353

45 minus 347347832238998282347923474237923794356473797838247236623236462684638

2 answers:

Juli2301 [7.4K]3 years ago

6 0

The answer would be 91938391

elixir [45]3 years ago

5 0

The answer is 6 :), I hope this helps <33!3&9/&

You might be interested in

Solve the problem. Susan purchased some municipal bonds yielding 7% annually and some certificates of deposit yielding 9% annual

romanna [79]

The equations would be

<span>Value: b + c = 19000
Interest: 0.07b + 0.09c = 1590

</span>0.07b + 0.09 (19,000 - b) = 1,590
0.07b + 1,710 - .09b = 1,590
<span>120 = .02b
</span>
B = 6,000
<span>C = 13,000
</span><span>
So the correct answer is </span><span>d. $6000 in bonds; $13,000 in certificates of deposit.
</span>
Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.

6 0

3 years ago

What are the best estimate for the amount of lemonade needed to serve six people

Romashka-Z-Leto [24]

Maybe six cups ? i’m not sure

6 0

2 years ago

Read 2 more answers

Unit rate of $42 for 3 books

HACTEHA [7]

I think it would be $14 per book

3 0

3 years ago

65 yard 2 feet = how many feet

stiv31 [10]

65 yards 2 feet = ?
1 yard = 3 feet

65(3)+2= 195+2 = 197

it is 197 feet

5 0

2 years ago

Read 2 more answers

I need to get the left side to equal the right side. Keeping the right side alone and not changing it.

likoan [24]

<u>To prove the trigonometric equation:</u>

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

$RHS=(\sin x+\cos x)(1-\sin x \cos x)$

We know that $\sin^2x +\cos^2x=1$ , substitute this in place of 1.

$=(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)$

Multiply each term of the first term with each term of the 2nd term.

$=\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x$

Group like terms together.

$=\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x$

$=\sin^3x +( 0)+(0) + \cos^3 x$

$=\sin^3x + \cos^3 x$

= LHS

RHS = LHS

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

Hence proved.

7 0

3 years ago