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andrew-mc [135]

3 years ago

8

97823843221623882623602794632621621738987345381237787733247697818473621883466325342536234347642375362374564357343525234766244353

45 minus 347347832238998282347923474237923794356473797838247236623236462684638

2 answers:

Juli2301 [7.4K]3 years ago

6 0

The answer would be 91938391

elixir [45]3 years ago

5 0

The answer is 6 :), I hope this helps <33!3&9/&

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Can someone pls explain this?

ryzh [129]

Answer:

A piecewise function.

Step-by-step explanation:

The problem you showed is a <em>piecewise function.</em>

In this problem, you have to plug in 3 for the value x.

However, if you take a look at the conditions that value x has, it never says that x can equal 3. <em>Thus, this function cannot be true.</em>

<em>Way to check this input is undefined: </em>

Plug in 3 for the variable x. On the first function, your output will be 4. On the second function, your output will be 8.

According to the definition of a function, a function can have many inputs but only one output. In this case, this function has one input, that is 3, but produces two outputs.

8 0

2 years ago

Alan rolls two number cubes. What is the probability that the sum of the two numbers will equal 9?

Ivahew [28]

The answer is 2/15 because it can either be 4 and 5 or 3 and 6

6 0

3 years ago

How would i solve. been getting wrong

Lisa [10]

Answer:just find a common denomintor and add them

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

In a previous exercise we formulated a model for learning in the form of the differential equation dp dt = k(m − p) where p(t) m

DaniilM [7]

I assume you mean

$\dfrac{dP}{dt} = k(M-P)$

ANSWER
An expression for P(t) is

$P = M - Me^{-kt}$

EXPLANATION
This is a separable differential equation. Treat M and k as constants. Then we can divide both sides by M - P to get the P term with the differential dP and multiply both sides by dt to separate dt from the P terms

$\begin{aligned} \dfrac{dP}{dt} &= k(M-P) \\ \dfrac{dP}{M-P} &= k\, dt
\end{aligned}$

Integrate both sides of the equation.

$\begin{aligned}
\int \dfrac{dP}{M-P} &= \int k\, dt \\
-\ln|M-P| &= kt + C \\
\ln|M-P| &= -kt - C\end{aligned}$

Note that for the left-hand side, u-substitution gives us

$u = M - P \implies du = -1dP \implies dP = -du$

hence why $\int \frac{dP}{M-P} \ne \ln|M - P|$

Now we use the definition of the logarithm to convert into exponential form.

The definition is

$\ln(a) = b \iff \log_e(a) = b \iff e^b = a$

so applying it here, we get

$\begin{aligned} \ln|M-P| &= -kt - C \\ |M - P| &= e^{-kt - C} \\ 
M - P &= \pm e^{-kt - C} 
 \end{aligned}$

Exponent properties can be used to address the constant C. We use $x^{a} \cdot x^{b} = x^{a+b}$ here:

$\begin{aligned}
 M - P &= \pm e^{-kt - C} \\
M - P &= \pm e^{- C - kt} \\ 
M - P &= \pm e^{- C + (- kt)} \\ 
M - P &= \pm e^{- C} \cdot e^{- kt} \\ 
M - P &= Ke^{- kt} && (\text{\footnotesize Let $K = \pm e^{-kt}$ }) \\ 
M &= Ke^{- kt} + P\\
P &= M - Ke^{- kt}
\end{aligned}$

If we assume that P(0) = 0, then set t = 0 and P = 0

$\begin{aligned} 
0 &= M - Ke^{- k\cdot 0} \\
0 &= M - K \cdot 1 \\
M &= K
 \end{aligned}
$

Substituting into our original equation, we get our final answer of

$P = M - Me^{-kt}$

6 0

3 years ago

Read 2 more answers

Number 6?? which of the following is the best estimate

makvit [3.9K]

its A.........dont u have a calculator

3 0

3 years ago