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Vinvika [58]
2 years ago
5

Round 93.0129 to the nearest thousandth

Mathematics
2 answers:
Semenov [28]2 years ago
7 0

Answer:

93.013

Step-by-step explanation:

the ansewer is 93.013

Xelga [282]2 years ago
3 0
The answer should be 93.013
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(Algebra 2) write a polynomial function of least degree with integral coefficients that has the given zeros.
saveliy_v [14]

Answer:

x^{2} -2ix+3=0 .

Step-by-step explanation:

Given the zeroes of the polynomial are

a=-i . and b=3i

The recquired polynomial is (x-a)(x-b)=0

On substituting the values of a and b we get

(x+i)(x-3i)=0

x^{2} -3xi+ix-3i^{2}=0

x^{2} -2ix+3=0 .       (∵i^{2}=-1)

6 0
2 years ago
Match the polynomial expression on the left with the simplified version on the right.
Vitek1552 [10]

Given the following question:

First expression:

\begin{gathered} \frac{12x^3-14x^2+16x-8}{3x-2} \\ \text{ Factor the expression:} \\ 12x^3-14x^2+16x-8=2(6x^3-7x^2+8x-4) \\ \frac{2\left(6x^3-7x^2+8x-4\right)}{3x-2} \\ \text{ Factor:} \\ 2\left(6x^3-7x^2+8x-4\right)=(3x-2)(2x^2-x+2) \\ =(3x-2)(2x^2-x+2)=2\left(3x-2\right)\left(2x^2-x+2\right) \\ \frac{2\left(3x-2\right)\left(2x^2-x+2\right)}{3x-2} \\ \text{ Cancel the common factor:} \\ -(3x-2) \\ 4x^2-2x+4 \end{gathered}

Second expression:

3 0
1 year ago
If the sides of a square are lengthened by 7 feet, the area becomes 121 square feet. How long is a side of the original square?
Bogdan [553]
Square root of 121 is 11.
11-7=4
A side of the original square is 4 feet.
5 0
3 years ago
Read 2 more answers
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



5 0
3 years ago
Read 2 more answers
Find the area of the following figure.
Zigmanuir [339]

Answer:

312

Step-by-step explanation:

Triangles

1/2 12 *10 = 6*10 = 60

there are two triangles meaning we have to multiply 60 by 2 = 120

Rectangle

12*16 = 192

Add the two and you have the area 120+192=312

5 0
2 years ago
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