Okay as dumb=b as it sounds, i have the answer but i cannot type it out on the computer..... the way i got this answer was through an app called "photomath". download it!! trust me you wont be disappointing because you can solve formulas like this<span />
Answer:
Step-by-step explanation:
(2.7)(10)
=27
27^4=531441
-------------------------------
(3.5)(10)
=35
35^3=42875
Answer:
s(t) = -4.9t² + 39.2t
Step-by-step explanation:
Given the projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s²
Given
g = -4.9m/s²
v0 = 39.2m/s
s0 = 0m (the initial height)
On substituting into the formula;
s(t) = gt² + v0t + s0
s(t) = -4.9t² + 39.2t + 0
s(t) = -4.9t² + 39.2t
This gives the equation that models the height
Answer:
b is 0
Step-by-step explanation:
yes, i am here :)
Answer:
v + u
Step-by-step explanation:
Using the rule of logarithms
log x + log y ⇔ log xy
Given
ln yx, then
ln yx = ln y + ln x = v + u
