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2 years ago

11

Please help! -3n+147=0

1 answer:

horrorfan [7]2 years ago

6 0

Answer:

n = ±7

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS
Equality Properties

<u>Algebra I</u>

Solving quadratics

Step-by-step explanation:

<u>Step 1: Define equation</u>

-3n² + 147 = 0

<u>Step 2: Solve for </u><em><u>n</u></em>

Subtract 147 on both sides: -3n² = -147
Divide -3 on both sides: n² = 49
Square root both sides: n = ±7

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Read 2 more answers

Rename 5/6 and 14/15 using the least common denominator.

baherus [9]

Answer:

$\frac{25}{30}~and~\frac{28}{30}$

Multiply 5 by 5 to get your first parameter.

$5 * 5 = 25$

Multiply 6 by 5 to get the denominator, or your second parameter.

$5 * 6 = 30$

For the second fraction, $\frac{14}{15}$ , you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

$14 * 2 = 28$

Now, multiply 15 by 2

$15 * 2 = 30$

The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

$25~and~30 -- > \frac{25}{30}$

$28~and~30-- > \frac{28}{30}$

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

________________________________________________________

<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0

2 years ago

you want to create a 99 confidence interval with a margin of error of 25 assuming that the population standard deviation is equa

Ahat [919]

Answer:

The minimum sample size is 239.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.99}{2} = 0.005$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.005 = 0.995$ , so Z = 2.575.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Population standard deviation is equal to 1.5

This means that $\sigma = 1.5$

Margin of error of 0.25

This means that $M = 0.25$

What's the minimum size of the sample?

$M = z\frac{\sigma}{\sqrt{n}}$

$0.25 = 2.575\frac{1.5}{\sqrt{n}}$

$0.25\sqrt{n} = 2.575*1.5$

$\sqrt{n} = \frac{2.575*1.5}{0.25}$

$(\sqrt{n})^2 = (\frac{2.575*1.5}{0.25})^2$

$n = 238.7$

Rounding up:

The minimum sample size is 239.

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3 years ago

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melamori03 [73]

Answer:

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Step-by-step explanation:

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3 years ago