All categories

2 years ago

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4

Mathematics

2 answers:

Lilit [14]2 years ago

5 0

Answer:

=28

Step-by-step explanation:

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4

3 (20-4) -4 ( 12 - 7)

60 - 12 -48 +28

= 28

Mrac [35]2 years ago

5 0

3 ( 5p - p ) - 4 ( 3p - 7 ) =

3 ( 4p ) - 12p + 28 =

12p - 12p + 28 =

0 + 28 = 28

Thus the value of p is not importent at all and the answer is always 28 .

You might be interested in

I need help so someone plz give me the steps and answer and graph it so i can understand how to solve these types of problems ag

Eddi Din [679]

Y + 6 = 4/5( x + 3)
y + 6 = 4/5x + (3(4))/5

y + 6 = 4/5x + (12)/5
y + 6 = 4/5x + 12/5
y + 6 (-6) = 4/5x + 12/5 (-6)
y = 4/5x + 12/5 (- 30/5)

y = 4/5x - 3.6 ( y = mx + b formula)

4/5 = 0.8

y = 0.8x - 3.6

x = 1
y = 0.8(1) - 3.6
y = - 2.8

x = 2
y = 0.8(2) - 3.6
y = 1.6 - 3.6
y = -2

x = 3
y = 0.8(3) - 3.6
y = 2.4 - 3.6
y = - 1.2

x = 4
y = 0.8(4) - 3.6
y = 3.2 - 3.6
y = - 0.4

x = 5
y = 0.8(5) - 3.6
y = 4 - 3.6
y = 0.4

etc.

graph using the (x,y)

connect the dots

hope this helps

8 0

2 years ago

Read 2 more answers

Are simplified ratios written in units?

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

Simplified ratios are not written in units.

8 0

2 years ago

\left(3x-5\right)+\left(x+6\right)

ryzh [129]

I'm sorry but I couldn't really get that can u at least take a picture or something

5 0

2 years ago

CJ = 3x + 6, CT = 37, and JT = 3x + 7 Find JT.

GrogVix [38]

Answer:

JT=19

Step-by-step explanation:

3x+6+3x+7=37

6x+6+7=37

6x+13=37

-13 -13

6x=24

6x/6=24/6

x=4

3x+7

3(4)+7

12+7

JT=19

3 0

3 years ago

Convert the following to standard form y=2/5 x - 1/3

Afina-wow [57]

Given :-

y = 2/5x - 1/3

To Find :-

To convert the given equation into standard form.

Solution :-

As we know that the standard form of the line is ,

$\sf\longrightarrow$ ax + by + c = 0

So the given equation is ,

$\sf\longrightarrow$ y = 2/5x -1/3

$\sf\longrightarrow$ y = 6x - 5/15

$\sf\longrightarrow$ 15y = 6x - 5

$\sf\longrightarrow$ 6x -15y -5 = 0

Hence the required equation of the line is 6x -15y-5=0.

8 0

2 years ago

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4​

3(5 p - 1 p ) - 4 ( 3 p -7) when p = 4