Answer:
1.65m
Step-by-step explanation:
First, we have to know the velocity of the ball in both axis, x-axis and y-axis.
Vy = sen(32.6°)*24m/s = 12.9m/s
Vx = cos(32.6°)*24m/s = 20.2m/s
Now, we are told the distance covered by the ball, which es 45m (x-axis). With that info, we can find the time the ball traveled, by x=v*t
x = distance in x-axis and Vx = 16.85m/s
Clearing t, we have: t = x / Vx = 45m / 20.2m/s = 2.2s
Finally, using the equation of vertical distance: Dy = 1/2 a*t² + V0y*t
Dy = (1/2*-9.8m/s²*2.2s²) + 12.9m/s*2.2s = -23.7m + 28.4m = 4.7m
The ball cleared the croosbar by 4.7m-3.05= 1.65m
